
This is the intensity one would get if the incident light consisted of 1) light with intensity
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polarized along

and 2) unpolarized light with intensity

. In order to be able to add the intensities as we have done, we need to assume that parts 1) and 2) are incoherent. %(see Giancoli page 873-874 and 877).
Assuming this, then answer (C) is correct.